. \% 说明：使用 xelatex 编译，在 texlive 2017 中编译通过
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\textbackslash\{\}usepackage[a4paper,top=2.0cm,bottom=2.5cm,left=2.8cm,right=2.8cm,\%
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\textbackslash\{\}usepackage\{makecell,interfaces-makecell\}
\textbackslash\{\}usepackage\{calc\}
\textbackslash\{\}renewcommand\{\textbackslash\{\}baselinestretch\}\{1.3\}

\%\%\%\%\% ===== 自定义命令 ===========================================================
\textbackslash\{\}newcommand\{\textbackslash\{\}ul\}[1]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[\#1]\{\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}ull\}[2]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[\#1]\{\textbackslash\{\}kaishu \#2\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}ulaa\}[1]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[3em]\{\textbackslash\{\}Large\textbackslash\{\}textcircled\{\textbackslash\{\}normalsize \#1\}\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}dis\}\{\textbackslash\{\}displaystyle\}

\textbackslash\{\}pagestyle\{plain\}

\textbackslash\{\}begin\{document\}
\textbackslash\{\}zihao\{-4\} \% 小四号字体

\%\%\%\%\% ===== 试卷头 ===============================================================
\textbackslash\{\}begin\{center\}
\{\textbackslash\{\}heiti\textbackslash\{\}LARGE 华东师范大学期末试卷 （A）\} \textbackslash\{\}bigskip

\$20xx-20xx\$ 学年第 X 学期

\textbackslash\{\}bigskip\textbackslash\{\}bigskip

\%\%\%\%\% ===== 课程信息，包括课程名，课程性质等
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\textbackslash\{\}renewcommand\{\textbackslash\{\}arraystretch\}\{1.4\}
\textbackslash\{\}begin\{tabular\}\{p\{7.5cm\}p\{6.5cm\}\}
  课程名称：\textbackslash\{\}ull\{4.0cm\}\{\textbackslash\{\}zihao\{4\} 数\~{}值\~{}分\~{}析\} \& \textbackslash\{\}\textbackslash\{\}
  学生姓名：\textbackslash\{\}ul\{4.0cm\}          \&
  学\textbackslash\{\}hspace\{10.5mm\}号：\textbackslash\{\}ul\{4.0cm\} \textbackslash\{\}\textbackslash\{\}
  专\textbackslash\{\}hspace\{2em\}业：\textbackslash\{\}ull\{4.0cm\}\{数学与应用数学\}  \&
  年级/班级：\textbackslash\{\}ull\{4.0cm\}\{20xx级\} \textbackslash\{\}\textbackslash\{\}
  课程性质：\textbackslash\{\} \{\textbackslash\{\}kaishu 专业X修\} \textbackslash\{\}\textbackslash\{\}
\textbackslash\{\}end\{tabular\}\textbackslash\{\}smallskip

\%\%\%\%\% ===== 得分表，其中 numexer 表示题号个数，这里设为 8，可根据实际需要修改，其他可以不用修改。
\textbackslash\{\}newcounter\{numexer\}\textbackslash\{\}setcounter\{numexer\}\{8\} \% 题号个数，这里为 8
\textbackslash\{\}newcounter\{numcol\}\textbackslash\{\}setcounter\{numcol\}\{\textbackslash\{\}value\{numexer\}+2\}
\textbackslash\{\}newlength\{\textbackslash\{\}cellwidth\}\textbackslash\{\}setlength\{\textbackslash\{\}cellwidth\}\{\textbackslash\{\}textwidth*\textbackslash\{\}ratio\{0.6pt\}\{\textbackslash\{\}value\{numexer\} pt\}\}
\textbackslash\{\}begin\{tabular\}\{|*\{\textbackslash\{\}thenumcol\}\{c|\}\} \textbackslash\{\}hline
  \textbackslash\{\}repeatcell\{\textbackslash\{\}thenumexer\}\{rows=1,text=\textbackslash\{\}makebox[\textbackslash\{\}cellwidth]\{\textbackslash\{\}zhnumber\{\textbackslash\{\}column\}\}\}
   \& \textbackslash\{\}makebox[0.12\textbackslash\{\}textwidth]\{总分\} \&\textbackslash\{\}makebox[0.16\textbackslash\{\}textwidth]\{阅卷人签名\} \textbackslash\{\}\textbackslash\{\} \textbackslash\{\}hline
  \textbackslash\{\}repeatcell\{\textbackslash\{\}thenumcol\}\{rows=1,end=\textbackslash\{\}\textbackslash\{\} \textbackslash\{\}hline\} \textbackslash\{\}\textbackslash\{\} \textbackslash\{\}hline
\textbackslash\{\}end\{tabular\}
\textbackslash\{\}end\{center\}

\textbackslash\{\}medskip
\textbackslash\{\}noindent\textbackslash\{\}dotfill
\textbackslash\{\}medskip

\textbackslash\{\}linespread\{1.5\}\textbackslash\{\}selectfont
\textbackslash\{\}noindent\{\textbackslash\{\}heiti 一、填充题\} （每空 2 分，共 24 分）

\textbackslash\{\}newcounter\{forlist\}
\textbackslash\{\}begin\{list\}\{\textbackslash\{\}arabic\{forlist\}.\}
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             \textbackslash\{\}setlength\{\textbackslash\{\}labelsep\}\{5pt\}
             \textbackslash\{\}setlength\{\textbackslash\{\}itemsep\}\{0.8em\}
             \textbackslash\{\}setlength\{\textbackslash\{\}parsep\}\{5pt\}
             \textbackslash\{\}usecounter\{forlist\}\}

\textbackslash\{\}item\% 说明：使用 xelatex 编译，在 texlive 2017 中编译通过
\%
\textbackslash\{\}documentclass[UTF8]\{ctexart\}
\textbackslash\{\}usepackage[a4paper,top=2.0cm,bottom=2.5cm,left=2.8cm,right=2.8cm,\%
includehead,includefoot]\{geometry\}
\textbackslash\{\}usepackage\{amsmath,amssymb,amsfonts,bm\}
\textbackslash\{\}usepackage\{graphicx,xcolor\}
\textbackslash\{\}usepackage[xetex,colorlinks,linkcolor=blue]\{hyperref\}
\textbackslash\{\}usepackage\{makecell,interfaces-makecell\}
\textbackslash\{\}usepackage\{calc\}
\textbackslash\{\}renewcommand\{\textbackslash\{\}baselinestretch\}\{1.3\}

\%\%\%\%\% ===== 自定义命令 ===========================================================
\textbackslash\{\}newcommand\{\textbackslash\{\}ul\}[1]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[\#1]\{\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}ull\}[2]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[\#1]\{\textbackslash\{\}kaishu \#2\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}ulaa\}[1]\{\textbackslash\{\}underline\{\textbackslash\{\}makebox[3em]\{\textbackslash\{\}Large\textbackslash\{\}textcircled\{\textbackslash\{\}normalsize \#1\}\}\}\}
\textbackslash\{\}newcommand\{\textbackslash\{\}dis\}\{\textbackslash\{\}displaystyle\}

\textbackslash\{\}pagestyle\{plain\}

\textbackslash\{\}begin\{document\}
\textbackslash\{\}zihao\{-4\} \% 小四号字体

\%\%\%\%\% ===== 试卷头 ===============================================================
\textbackslash\{\}begin\{center\}
\{\textbackslash\{\}heiti\textbackslash\{\}LARGE 华东师范大学期末试卷 （A）\} \textbackslash\{\}bigskip

\$20xx-20xx\$ 学年第 X 学期

\textbackslash\{\}bigskip\textbackslash\{\}bigskip

\%\%\%\%\% ===== 课程信息，包括课程名，课程性质等
\textbackslash\{\}setlength\{\textbackslash\{\}tabcolsep\}\{1mm\}
\textbackslash\{\}renewcommand\{\textbackslash\{\}arraystretch\}\{1.4\}
\textbackslash\{\}begin\{tabular\}\{p\{7.5cm\}p\{6.5cm\}\}
课程名称：\textbackslash\{\}ull\{4.0cm\}\{\textbackslash\{\}zihao\{4\} 数\~{}值\~{}分\~{}析\} \& \textbackslash\{\}\textbackslash\{\}
学生姓名：\textbackslash\{\}ul\{4.0cm\}          \&
学\textbackslash\{\}hspace\{10.5mm\}号：\textbackslash\{\}ul\{4.0cm\} \textbackslash\{\}\textbackslash\{\}
专\textbackslash\{\}hspace\{2em\}业：\textbackslash\{\}ull\{4.0cm\}\{数学与应用数学\}  \&
年级/班级：\textbackslash\{\}ull\{4.0cm\}\{20xx级\} \textbackslash\{\}\textbackslash\{\}
课程性质：\textbackslash\{\} \{\textbackslash\{\}kaishu 专业X修\} \textbackslash\{\}\textbackslash\{\}
\textbackslash\{\}end\{tabular\}\textbackslash\{\}smallskip

\%\%\%\%\% ===== 得分表，其中 numexer 表示题号个数，这里设为 8，可根据实际需要修改，其他可以不用修改。
\textbackslash\{\}newcounter\{numexer\}\textbackslash\{\}setcounter\{numexer\}\{8\} \% 题号个数，这里为 8
\textbackslash\{\}newcounter\{numcol\}\textbackslash\{\}setcounter\{numcol\}\{\textbackslash\{\}value\{numexer\}+2\}
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\& \textbackslash\{\}makebox[0.12\textbackslash\{\}textwidth]\{总分\} \&\textbackslash\{\}makebox[0.16\textbackslash\{\}textwidth]\{阅卷人签名\} \textbackslash\{\}\textbackslash\{\} \textbackslash\{\}hline
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\textbackslash\{\}end\{tabular\}
\textbackslash\{\}end\{center\}

\textbackslash\{\}medskip
\textbackslash\{\}noindent\textbackslash\{\}dotfill
\textbackslash\{\}medskip

\textbackslash\{\}linespread\{1.5\}\textbackslash\{\}selectfont
\textbackslash\{\}noindent\{\textbackslash\{\}heiti 一、填充题\} （每空 2 分，共 24 分）

\textbackslash\{\}newcounter\{forlist\}
\textbackslash\{\}begin\{list\}\{\textbackslash\{\}arabic\{forlist\}.\}
\{\textbackslash\{\}setlength\{\textbackslash\{\}topsep\}\{2mm\}
\textbackslash\{\}setlength\{\textbackslash\{\}listparindent\}\{0pt\}
\textbackslash\{\}setlength\{\textbackslash\{\}labelsep\}\{5pt\}
\textbackslash\{\}setlength\{\textbackslash\{\}itemsep\}\{0.8em\}
\textbackslash\{\}setlength\{\textbackslash\{\}parsep\}\{5pt\}
\textbackslash\{\}usecounter\{forlist\}\}

\textbackslash\{\}item
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{1\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{2\})\_\{10\}\$。

\textbackslash\{\}item
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{3\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{4\})\_\{10\}\$。

\textbackslash\{\}item
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{5\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{6\})\_\{10\}\$。


\textbackslash\{\}end\{list\}


\textbackslash\{\}newpage
\textbackslash\{\}linespread\{1.3\}\textbackslash\{\}selectfont

\textbackslash\{\}begin\{list\}\{\textbackslash\{\}heiti\textbackslash\{\}Chinese\{forlist\}、\}
\{\textbackslash\{\}setlength\{\textbackslash\{\}topsep\}\{1mm\}
\textbackslash\{\}setlength\{\textbackslash\{\}listparindent\}\{0pt\}
\textbackslash\{\}setlength\{\textbackslash\{\}itemsep\}\{2em\}
\textbackslash\{\}setlength\{\textbackslash\{\}labelsep\}\{0pt\}
\textbackslash\{\}usecounter\{forlist\}
\textbackslash\{\}setcounter\{forlist\}\{1\}\}

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv x\^{}k \$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$); \textbackslash\{\}\textbackslash\{\}
（2）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n (x\_j-x)\^{}k l\_j(x) \textbackslash\{\}equiv 0\$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$)。

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv x\^{}k \$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$); \textbackslash\{\}\textbackslash\{\}
（2）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n (x\_j-x)\^{}k l\_j(x) \textbackslash\{\}equiv 0\$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$)。

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{1\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{2\})\_\{10\}\$。

\textbackslash\{\}item
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{3\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{4\})\_\{10\}\$。

\textbackslash\{\}item
十进制数与二进制数的转换： \$(123)\_\{10\}= (\textbackslash\{\}ulaa\{5\})\_2\$，
\$(110)\_2 = (\textbackslash\{\}ulaa\{6\})\_\{10\}\$。


\textbackslash\{\}end\{list\}


\textbackslash\{\}newpage
\textbackslash\{\}linespread\{1.3\}\textbackslash\{\}selectfont

\textbackslash\{\}begin\{list\}\{\textbackslash\{\}heiti\textbackslash\{\}Chinese\{forlist\}、\}
            \{\textbackslash\{\}setlength\{\textbackslash\{\}topsep\}\{1mm\}
             \textbackslash\{\}setlength\{\textbackslash\{\}listparindent\}\{0pt\}
             \textbackslash\{\}setlength\{\textbackslash\{\}itemsep\}\{2em\}
             \textbackslash\{\}setlength\{\textbackslash\{\}labelsep\}\{0pt\}
             \textbackslash\{\}usecounter\{forlist\}
             \textbackslash\{\}setcounter\{forlist\}\{1\}\}

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv x\^{}k \$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$); \textbackslash\{\}\textbackslash\{\}
（2）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n (x\_j-x)\^{}k l\_j(x) \textbackslash\{\}equiv 0\$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$)。

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv x\^{}k \$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$); \textbackslash\{\}\textbackslash\{\}
（2）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n (x\_j-x)\^{}k l\_j(x) \textbackslash\{\}equiv 0\$\textbackslash\{\}quad (\$k=0,1,\textbackslash\{\}ldots,n\$)。

\textbackslash\{\}item （15 分） \% ========================================================
设 \$x\_0,x\_1,\textbackslash\{\}ldots,x\_n\$ 为互异节点，求证: \textbackslash\{\}\textbackslash\{\}[1ex]
（1）\$\textbackslash\{\}dis\textbackslash\{\}sum\textbackslash\{\}limits\_\{j=0\}\^{}n x\_j\^{}k l\_j(x) \textbackslash\{\}equiv